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# 1672. Richest Customer Wealth

🟩 Easy

You are given an `m x n` integer grid `accounts` where `accounts[i][j]` is the amount of money the `i^th` customer has in the `j^th` bank. Return *the **wealth** that the richest customer has.*

A customer's **wealth** is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum **wealth**.

## Example 1

> **Input**: accounts = \[\[1,2,3],\[3,2,1]]\
> **Output**: 6\
> **Explanation**:\
> 1st customer has wealth = 1 + 2 + 3 = 6\
> 2nd customer has wealth = 3 + 2 + 1 = 6\
> Both customers are considered the richest with a wealth of 6 each, so return 6.

## Example 2

> **Input**: accounts = \[\[1,5],\[7,3],\[3,5]]\
> **Output**: 10\
> **Explanation**:\
> 1st customer has wealth = 6\
> 2nd customer has wealth = 10\
> 3rd customer has wealth = 8\
> The 2nd customer is the richest with a wealth of 10.

## Example 3

> **Input**: accounts = \[\[2,8,7],\[7,1,3],\[1,9,5]]\
> **Output**: 17

## Constraints

* `m == accounts.length`
* `n == accounts[i].length`
* `1 <= m, n <= 50`
* `1 <= accounts[i][j] <= 100`

## Hint-1

> Calculate the wealth of each customer

## Hint-2

> Find the maximum element in array.

## Solution

My Solution

```go
func maximumWealth(accounts [][]int) int {
    max := 0
    for _, i := range accounts {
        sum := 0
        for _,j := range i {
            sum+=j
        }
        if sum > max {
            max = sum
        }
    }
    return max
}
```

![result](https://600345290-files.gitbook.io/~/files/v0/b/gitbook-x-prod.appspot.com/o/spaces%2FrSK2xH3txU3tYyDsT8mQ%2Fuploads%2Fgit-blob-ca5b34eaae6461796efc3b99bfde7da8e69c5ec2%2F1672.png?alt=media)

Leetcode: [link](https://leetcode.com/problems/richest-customer-wealth/description/)