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# 58. Length of Last Word

🟩 Easy

Given a string `s` consisting of words and spaces, return *the length of the **last** word in the string*.

A **word** is a maximal `substring` consisting of non-space characters only.

Example 1:

Input: Output: 5 Explanation: Example 2:

Input: Output: 4 Explanation: Example 3:

Input: Output: 6 Explanation:

Constraints:

## Example 1

> **Input**: s = "Hello World"\
> **Output**: 5\
> **Explanation**: The last word is "World" with length 5.

## Example 2

> **Input**: s = " fly me to the moon "\
> **Output**: 4\
> **Explanation**: The last word is "moon" with length 4.

## Example 3

> **Input**: s = "luffy is still joyboy" **Output**: 6\
> **Explanation**: The last word is "joyboy" with length 6.

## Constraints

* `1 <= s.length <= 10^4`
* `s` consists of only English letters and spaces `' '`.
* There will be at least one word in `s`.

## Solution

My Solution

```go
func lengthOfLastWord(s string) int {
    cnt := 0
    existEmpty := false
    for _, v := range s {
        if v == ' ' {
            existEmpty = true
        } else {
            if existEmpty {
                cnt = 0
                existEmpty = false
            }
            cnt++
        }
    }

    return cnt
}
```

Optimal solution

```go
func lengthOfLastWord(s string) int {
    length := 0
    i := len(s) - 1

    // Ignore trailing spaces
    for i >= 0 && s[i] == ' ' {
        i--
    }

    // Count the length of the last word
    for i >= 0 && s[i] != ' ' {
        length++
        i--
    }

    return length
}
```

![result](/files/w6lACbjbjn46vODaOTH6)

Leetcode: [link](https://leetcode.com/problems/length-of-last-word/description)