> For the complete documentation index, see [llms.txt](https://leetcode.realtemirov.uz/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://leetcode.realtemirov.uz/problems/283.-move-zeroes.md).

# 283. Move Zeroes

🟩 Easy

Given an integer array `nums`, move all `0`'s to the end of it while maintaining the relative order of the non-zero elements.

**Note** that you must do this in-place without making a copy of the array.

## Example 1

> **Input**: nums = \[0,1,0,3,12]\
> **Output**: \[1,3,12,0,0]

## Example 2

> **Input**: nums = \[0]\
> **Output**: \[0]

## Constraints

* `1 <= nums.length <= 10^4`
* `-2^31 <= nums[i] <= 2^31 - 1`

**Follow up**: Could you minimize the total number of operations done?

## Hint-1

> **In-place** means we should not be allocating any space for extra array. But we are allowed to modify the existing array. However, as a first step, try coming up with a solution that makes use of additional space. For this problem as well, first apply the idea discussed using an additional array and the in-place solution will pop up eventually.

## Hint-2

> A **two-pointer** approach could be helpful here. The idea would be to have one pointer for iterating the array and another pointer that just works on the non-zero elements of the array.

## Solution

My Solution

```go
func moveZeroes(nums []int)  {
    idx := 0
    for _, num := range nums {
        if num != 0 {
            nums[idx] = num
            idx++
        }
    }

    for i:=idx; i<len(nums); i++ {
        nums[i]=0
    }
}
```

![result](https://600345290-files.gitbook.io/~/files/v0/b/gitbook-x-prod.appspot.com/o/spaces%2FrSK2xH3txU3tYyDsT8mQ%2Fuploads%2Fgit-blob-fa64c9efa49bdd1f02bb72af5d0ca86d3e9eb88d%2F283.png?alt=media)

Leetcode: [link](https://leetcode.com/problems/move-zeroes/description/)


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