238. Product of Array Except Self

🟧 Medium

Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the elements of nums except nums[i].

The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.

You must write an algorithm that runs in O(n) time and without using the division operation.

Example 1

Input: nums = [1,2,3,4] Output: [24,12,8,6]

Example 2

Input: nums = [-1,1,0,-3,3] Output: [0,0,9,0,0]

Constraints

  • 2 <= nums.length <= 10^5

  • -30 <= nums[i] <= 30

  • The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.

Follow up: Can you solve the problem in O(1) extra space complexity? (The output array does not count as extra space for space complexity analysis.)

Solution

My Solution

func productExceptSelf(nums []int) []int {
  res := make([]int, len(nums))

    left := 1
    for i ,num := range nums {
        res[i]=left
        left *= num
    }
    
    right := 1
    for i:=len(nums)-1; i>=0; i-- {
        res[i]*=right
        right*=nums[i]
    }

  return res
}

Optimal Solution

The optimal solution uses prefix and suffix products without using division:

func productExceptSelf(nums []int) []int {
    n := len(nums)
    result := make([]int, n)
    
    // Initialize result array with 1s
    result[0] = 1
    
    // Calculate prefix products
    for i := 1; i < n; i++ {
        result[i] = result[i-1] * nums[i-1]
    }
    
    // Calculate suffix products and combine with prefix
    suffix := 1
    for i := n-1; i >= 0; i-- {
        result[i] *= suffix
        suffix *= nums[i]
    }
    
    return result
}

Approach Analysis

The solution uses two key techniques:

  1. Prefix Products:

    • Calculate products of all elements to the left

    • Store intermediate results in output array

    • Build up products from left to right

  2. Suffix Products:

    • Calculate products of all elements to the right

    • Combine with prefix products

    • Use single variable to save space

Visualization of Both Approaches

Input: [1,2,3,4]

Step 1: Calculate Prefix Products
Initial: [1, _, _, _]
After 1: [1, 1, _, _]
After 2: [1, 1, 2, _]
After 3: [1, 1, 2, 6]

Step 2: Calculate Suffix Products
suffix = 1
[1, 1, 2, 6] * [24, 12, 4, 1]
= [24, 12, 8, 6]

Detailed Steps:
i=3: result[3] = 6 * 1 = 6,    suffix = 4
i=2: result[2] = 2 * 4 = 8,    suffix = 12
i=1: result[1] = 1 * 12 = 12,  suffix = 24
i=0: result[0] = 1 * 24 = 24,  suffix = 24

Final Result: [24, 12, 8, 6]

Complexity Analysis

Time Complexity:

  • O(n) - two passes through the array

  • First pass: prefix products

  • Second pass: suffix products

  • No nested loops

Space Complexity:

  • O(1) - excluding output array

  • Only one extra variable (suffix)

  • Output array not counted as extra space

Optimizations:

  • No division operation used

  • Reuse output array for prefix products

  • Single variable for suffix products

  • No extra arrays needed

Why Solution Works

  1. Prefix-Suffix Combination:

    • Each position gets products from both sides

    • Left products stored in result array

    • Right products multiplied during second pass

    • Avoids division operation

  2. Space Optimization:

    • Reuses output array for intermediate results

    • Needs only one extra variable

    • Maintains O(1) extra space

    • Efficient memory usage

  3. Two-Pass Approach:

    • First pass builds left products

    • Second pass combines with right products

    • Each element gets complete product

    • Handles zeros naturally

When to Use

This approach is ideal when:

  1. Division operation is not allowed

  2. O(1) extra space required

  3. Need products of all elements except self

  4. Array elements can be positive/negative/zero

Common applications:

  • Array transformation problems

  • Product calculations without division

  • Space-constrained environments

  • Interview problems

Common Patterns & Applications

  1. Prefix-Suffix Pattern:

    • Build products from both directions

    • Combine intermediate results

    • Use output array for storage

    • O(1) extra space

  2. Two-Pass Array:

    • Forward pass for prefix

    • Backward pass for suffix

    • Combine results in-place

    • Space-efficient solution

  3. Array Manipulation:

    • In-place modifications

    • Running products

    • Direction-based processing

    • Space optimization

Interview Tips

  1. Initial Clarification:

    • Confirm if division is allowed

    • Ask about space constraints

    • Clarify handling of zeros

    • Discuss integer overflow

  2. Solution Walkthrough:

    • Start with brute force approach

    • Explain space optimization

    • Show how to avoid division

    • Demonstrate two-pass technique

  3. Code Implementation Strategy:

    • Initialize result array

    • Implement prefix products

    • Add suffix products

    • Handle edge cases

  4. Optimization Discussion:

    • Why division is problematic

    • How to save space

    • Handling large numbers

    • Performance considerations

  5. Common Pitfalls to Avoid:

    • Using division

    • Creating extra arrays

    • Missing edge cases

    • Integer overflow

  6. Follow-up Questions:

    • Q: "How to handle integer overflow?" A: Use long/big integers or modulo arithmetic

    • Q: "Can we optimize for arrays with zeros?" A: Count zeros and handle special cases

    • Q: "How to parallelize this solution?" A: Split array and combine partial products

    • Q: "What if array is very large?" A: Consider chunking and parallel processing

  7. Edge Cases to Test:

    • Array with zeros

    • Array with negative numbers

    • Array with ones

    • Minimum length array (2)

    • Maximum length array

  8. Code Quality Points:

    • Clear variable names

    • Efficient array initialization

    • Clean loop logic

    • Proper comments

  9. Alternative Approaches:

    • Using logarithms (not recommended)

    • Division-based (if allowed)

    • Recursive solution

    • Parallel processing

  10. Performance Analysis:

    • Best case: O(n)

    • Worst case: O(n)

    • Memory: O(1)

    • CPU cache friendly

result

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